A Box Slides Down An Inclined Plane With A Uniform Acceleration And Attains A Velocity Of 27 M/S In 3 Seconds From Rest. Find The Final Velocity And D

A box slides down an inclined plane with a uniform acceleration and attains a velocity of 27 m/s in 3 seconds from rest. Find the final velocity and distance moved in 6 seconds(initially at rest).

 

Good Day

Problem:

A box slides down an inclined plane with a uniform acceleration and attains a velocity of 27 m/s in 3 seconds from rest. Find the final velocity and distance moved in 6 seconds(initially at rest).

Answer:

54 m/s is the final velocity in 6 seconds when its acceleration is 9 m/s²

First we have to compute first for acceleration to find the final velocity in 6 seconds

Given Data:

Vi (initial velocity)  =  0 m/s  (at rest)

Vf (final velcity)= 27 m/s

t (time)  =  3 s

acceleration = unknown

Solution:

a = Vf-Vi/t

  = 27 m/s - 0m/s / 3 s

  = 27 m/s / 3 s

  = 9 m/s²

To solve for Final velocity at 6 seconds:

Given:

Vi (initial velocity)  =  0 m/s  (at rest)

Vf (final velcity)= ? unknown

t (time)  =  6 s

acceleration = 9 m/s²

Solution:

Vf = at + Vi

   = 9 m/s² × 6 s  + 0 m/s

   = 54 m/s

Hope it helps....=)